In python, we can find the ascii value using ord of a string
>>> ord('a')
97
>>> ord('A')
65
>>> ord('b')
98
>>> ord('1')
49
>>> ord('2')
50
>>> 3-0
3
>>> ord('3')-ord('0')
3
Notice how the lower case and upper case are unique. Also, the ASCII numeric value and the character increase by the same amount. The same trend is true for the continuation of the alphabet, if lower case or upper case characteristic is preserved. The string length must be 1 when using ord, because each index has its own ASCII value.For a multiple digit number or a word, you can use a for loop to go through the string.
The reverse of ord is chr, for character.
>>> chr(97)
'a'
>>> i=97
>>> while i<104:
... print chr(i)
... i+=1
...
a
b
c
d
e
f
g
>>> alpha=[]
>>> i=97
>>> while i<104:
... alpha.append(chr(i))
... i+=1
...
>>> print alpha
['a', 'b', 'c', 'd', 'e', 'f', 'g']
Caesar's shift was how Caesar communicated with his generals, in which each letter in the plaintext is replaced by a letter some fixed number of positions down the alphabet. For example, if an 'a' is encoded by a 'c' with a shift of 2, then a 'b' would be encoded by a 'd.' Reversely, an 'a' in the encoded text would be a 'y' in the plaintext. The following program was inspired by thepythonchallenge.com. My husband and I had a lot of fun testing and debugging by sending each other messages over email. The code only changes letters so that spaces, smilies, brackets, and other punctuations and characters will be preserved. string.maketrans would be very useful and less code for a one time application, but the following code is highly reusable.
#string will later allow us to test for ascii letters
import string
def encode(input,shift):
#create an empty string
foo = ''
#a for loop to shift the letters by the shift input
for x in input:
#changes only ascii letters
if x in string.ascii_letters:
#upper case end of alphabet, to loop back to A
if ord(x) > ord("Z") - shift and ord(x) <= ord("Z"):
new_ord = ord(x) + shift - 26
#lower case end of alphabet
elif ord(x) > ord("z") - shift and ord(x) <= ord("z"):
new_ord = ord(x) + shift - 26
else:
new_ord = ord(x) + shift
#other characters will remain unchanged
else:
new_ord = ord(x)
new_chr = chr(new_ord)
foo += new_chr
print "Your encoded message is ", foo
def decode(input,shift):
#create an empty string
foo = ''
#a for loop to shift the leters by the shift input
for x in input:
#changes only ascii letters
if x in string.ascii_letters:
#upper case start of alphabet, to loop back to Z
if ord(x) - shift < ord("A") and ord(x) >= ord("A"):
new_ord = ord(x) - shift + 26
#lower case end of alphabet
elif ord(x) - shift < ord("a") and ord(x) >= ord("a"):
new_ord = ord(x) - shift + 26
else:
new_ord = ord(x) - shift
#other characters will remain unchanged
else:
new_ord = ord(x)
new_chr = chr(new_ord)
foo += new_chr
print "Your decoded message is ", foo
def get_shift():
try:
shift = int(raw_input("How many characters do you want to\
shift?\n"))
except:
print 'Shift must be a number'
shift = get_shift()
if not (shift > 0 and shift <= 25):
print 'Shift must be between 1 and 25'
shift = get_shift()
return shift
def main():
try:
action=raw_input("Welcome to Caeser's Shifter! Would you \
like to encode or decode a message today?\n")
except:
print 'Please type encode or decode'
main()
shift = get_shift()
print "Ok, let's %s your message with a shift of %d." % (action, shift)
input=raw_input("What would you like to be translated?\n")
if action=='encode':
encode(input,shift)
elif action=='decode':
decode(input,shift)
if __name__ == "__main__":
main()
There are probably a few areas where redundancy can be reduced, but I am still learning as a developer. This was my first time trying exception handling, which I learned from my husband.